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Glacius
ProbabilityConcept reference

Central limit theorem

A centered IID sum divided by σ√n approaches the standard normal distribution when individual variance is finite and positive.

On this page 8 sections
  1. Overview
  2. The central limit theorem describes the shape of fluctuations in large sums or averages
  3. Conditional on using a normal approximation, model the sum by N(nμ,nσ^2)
  4. The approximation describes a sum or average, not the raw observations
  5. This can approximate accumulated independent errors or uncertainty in a sampled average
  6. Key takeaway
  7. Sources & further reading
  8. Concept connections

01The central limit theorem describes the shape of fluctuations in large sums or averages#

The central limit theorem describes the shape of fluctuations in large sums or averages. Under the IID, finite-positive-variance version used here, a properly centered and scaled sum approaches a standard normal distribution. The original observations do not need to look bell-shaped.

The law of large numbers concerns where an average settles. The CLT describes a scale and limiting shape for its deviations. Keep the quantity being approximated clear: a sum and an average have different means and standard deviations.

IID draws have mean μ\mu and finite positive variance σ2\sigma^2. For their sum SnS_n, define:

Zn=SnnμσnZ_n=\frac{S_n-n\mu}{\sigma\sqrt n}

The CLT gives a standard normal limit as n grows.

A sum of 100 draws with mean 2 and variance 9 has mean 200 and variance 900. The sum’s standard deviation is 30.

For 100 IID draws with mean 2 and variance 9, the sum has exact mean 200 and variance 900, hence SD 30. The drawn normal curve with mean 200 and SD 30 is the CLT approximation, not the exact finite-sample law.For 100 IID draws with mean 2 and variance 9, the sum has exact mean 200 and variance 900, hence SD 30. The drawn normal curve with mean 200 and SD 30 is the CLT approximation, not the exact finite-sample law.
Figure 1For 100 IID draws with mean 2 and variance 9, the sum has exact mean 200 and variance 900, hence SD 30. The drawn normal curve with mean 200 and SD 30 is the CLT approximation, not the exact finite-sample law.
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For 100 IID draws with mean 2 and variance 9, the sum has mean 100(2)=200100(2)=200 and variance 100(9)=900100(9)=900. Its SD is 30. An observed sum of 230 is (230200)/30=1(230-200)/30=1 standardized unit above its mean. Dividing by 900 would use variance where the standard deviation is required.

Check your reasoning

IID mean 33, variance 99. Normal model for a 44-draw sum: (mean, variance)?

  1. A(12,144)(12, 144)
  2. B(12,9)(12, 9)
  3. C(12,36)(12, 36)
Show answer and explanation
(12,36)(12, 36)

4×(3,9)=(12,36).

02Conditional on using a normal approximation, model the sum by N(nμ,nσ^2)#

Conditional on using a normal approximation, model the sum by N(nμ,nσ2)N(n\mu,n\sigma^2). The second parameter here is variance.

Subtract the sum’s mean, then divide by its standard deviation. Dividing by n times the individual SD would use the wrong scale.

Check your reasoning

IID errors have mean 22 and SD 44. For 99 errors, observed sum is 1212. Find its standardized value.

Show answer and explanation
-0.5

Center at 1818 and divide by sum SD 1212: the standardized value is 0.5-0.5.

03The approximation describes a sum or average, not the raw observations#

The approximation describes a sum or average, not the raw observations. Those observations may remain discrete or skewed.

The CLT is asymptotic. It supplies no universal sample size that guarantees a chosen accuracy; inspect those assumptions and accuracy separately.

Check your reasoning

IID: mean 44, variance 44. Draft variance 324324 for their 99-draw sum. Correct (mean, variance).

  1. A(36,324)(36, 324)
  2. B(36,36)(36, 36)
  3. C(36,4)(36, 4)
Show answer and explanation
(36,36)(36, 36)

9×4=369\times4=36 for both.

04This can approximate accumulated independent errors or uncertainty in a sampled average#

This can approximate accumulated independent errors or uncertainty in a sampled average. There is no universal sample-size cutoff that guarantees accuracy for every distribution. Heavy tails, dependence, or an extreme-tail probability can make a simple normal approximation unreliable.

Key takeaway

For the sum, use mean nμ and variance nσ²; standardize with σ√n and treat normality as an approximation.

  • Form a normal approximation for a standardized IID sum with finite positive variance.

Sources & further reading

  1. [1]

Reference this concept

Link to this page, a section, or an individual figure.

Glacius. “Central limit theorem.” Math behind ML. /learn/p-clt